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STD 11 - 7. Redox reactions — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 7. Redox reactions4 Marks
Question
Oxidation number of $C$ in $HNC$ is
✓

Answer

$H-\stackrel{..}{N}\stackrel{\rightarrow}{=}C$

$+1 \; \stackrel{-1}{-2}\,+2$

direction of co-ordinate bond is from more $EN$ atom to less $EN$ atom. So there is no development of charge due to this co-ordinate bond.

So in $\mathrm{HNC} \Rightarrow$

$\mathrm{O} \cdot \mathrm{N} \text { of } \mathrm{H}=+1$

$\mathrm{O} \cdot \mathrm{N}$ of $\mathrm{N}=-3$

$\mathrm{O} \cdot \mathrm{N}$ of $\mathrm{C}=+2$

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