MCQ
Oxidation number of C in HNC is_________.
- A+2
- B−3
- C+3
- DZero
✓
Answer
- +2
Explanation:
Oxidation number of hydrogen is +1. As nitrogen is more electronegative than carbon so its oxidation number is -3. Net charge on compound is zero.
Now we can find oxidation number of carbon:
Let oxidation number of carbon is x,
1 + (−3) + x = 0
x = +2
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following sets of quantum numbers is correct for an electron in $4f$ orbital
→Propene when heated with chlorine at about ${500\,^o}C$ forms
→Benzene cannot undergo
Pair of metamers is :-
The maximum number of electrons in a orbital is:
Calculate the minimum concentration of sulphate ion required to precipitate $BaSO_4$ in solution containing $10^{-4}\,mol/L$ of $Ba^{+2}$ . $(K_{sp} \,BaSO_4 = 4 \times 10^{-10})$
→Consider the following flow diagram :-
→Compound $X$ and $Y$ are respectively.
Which of the following oxides will not give $O{H^ - }$ in aqueous solution
→In the given reaction, the oxide of sodium is ….$\left[ {\begin{array}{*{20}{c}}{4Na + {O_2} \to 2N{a_2}O}\\{N{a_2}O + {H_2}O \to 2NaOH}\end{array}} \right]$
→$M$ is
→