MCQ
Oxidation number of $Fe$ in ${K_3}[Fe{(CN)_6}]$ is
- A$+2$
- ✓$+3$
- C$+1$
- D$+4$
$1 \times 3 + x + ( - 1 \times 6) = 0$
$3 + x - 6 = 0$; $x = + 3$.
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