Oxidation number of nitrogen in NaN O_2 is - Vidyadip

MCQ

Oxidation number of nitrogen in $NaN{O_2}$ is

A
$+2$
✓
$+3$
C
$+4$
D
$-3$

✓

Answer

Correct option: B.

$+3$

(b) Let the oxidation number of $N$ in $NaN{O_2}$ be $x$

$ + 1 + x + ( - 2) \times 2 = 0$

$1 + x - 4 = 0$; $x = + 3$

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