MCQ
Oxidation number of $S$ in ${S_2}C{l_2}$ is
- ✓$+1$
- B$- 1$
- C$+6$
- D$0$
$2x + 2( - 1) = 0$; $2x - 2 = 0$
$x = + 1$.
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$2$ $[image]$ + $\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,} \\
{H - C - CC{l_3}}
\end{array}$ $\xrightarrow{{{H_2}S{O_4}}}$
The major product formed is

$(A)$ Upon heating, $H _3 PO _3$ undergoes disproportionation reaction to produce $H _3 PO _4$ and $PH _3$.
$(B)$ While $H _3 PO _3$ can act as reducing agent, $H _3 PO _4$ cannot.
$(C)$ $H _3 PO _3$ is a monobasic acid.
$(D)$ The $H$ atom of $P - H$ bond in $H _3 PO _3$ is not ionizable in water.