Question
Oxidation state of chlorine in perchloric acid is
$1 + x - 2 \times 4 = 0;\,\,1 + x - 8 = 0$
$x = 8 - 1 = + 7$ oxidation state.
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${{H}_{2}}+C{{l}_{2}}\xrightarrow{\text{Sunlight}}2HCl$
(Given: Atomic mass of $\mathrm{C}=12, \mathrm{H}=1, \mathrm{O}=16 \mathrm{u}$ )