MCQ
Oxidising action increases in halogen in the following order
- A$Cl < Br < I < F$
- B$Cl < I < Br < F$
- C$I < F < Cl < Br$
- ✓$I < Br < Cl < F$
Among halogens $F$ is the directly most powerful oxidising agent.
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$(a)\; C \;\;(b)\; O \;\;(c)\; F\;\; (d) \;Cl\;\; (e)\; Br$
(Given that : $SrCO_{3(s)} \rightleftharpoons SrO_{(s)}+ CO_{2(g)} \,, K_p=1.6\,atm$)
