$p-$ aminophenol reacts with one equivalent of acetyl chloride in the presence of pyridine to give mainly
A
B
C
D
Medium
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D
d $(d)$ Acetylation reaction, $\ddot{N}{{H}_{2}}$ group will be dominent than $ -\ddot{\underset{\scriptscriptstyle\centerdot\centerdot}{O}}H$ group.
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Hoffmann bromomide degradation of benzamide gives product $A$, which upon heating with $CHCl _{3}$ and $NaOH$ gives product $B$. The structures of $A$ and $B$ are
A given nitrogen-containing aromatic compound $'A'$ reacts with $Sn/HCl,$ followed by $HNO_2$ to give an unstable compound $'B'$. $ 'B',$ on treatment with phenol, forms a beautiful coloured compound $'C'$ with the molecular formula $C_{12}H_{10}N_2O.$ The structure of compound $'A'$ is