
Statement $II :$ The lone pair of electrons on nitrogen in pyridine makes it basic.
Choose the CORRECT answer from the options given below:
Product $(B)$ is

${C_6}{H_5} - N{H_2}\xrightarrow[{HCl}]{{NaN{O_2}}}A\xrightarrow{{CuCN}}B\xrightarrow{{{H_2}/Ni}}C\xrightarrow{{HN{O_2}}}D$
product $(D)$ would be