MCQ
P is a point on side $BC$ of a $\triangle\text{ABC}$ such that AP bisects $\angle\text{BAC}.$ Then,
- A$BP = CP$
- B$CP < CA$
- ✓$BA > BP$
- D$BP > BA$
✓
Answer
Correct option: C.
$BA > BP$
Since, $AP$ bisects $\angle\text{BAC}.$
Hence the point $P$ on $BC$ also bisects it as it the opposite side of $\angle\text{BAC}.$
Hence, we can conclude that, $BA > BP.$
Hence the point $P$ on $BC$ also bisects it as it the opposite side of $\angle\text{BAC}.$
Hence, we can conclude that, $BA > BP.$
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