MCQ
$P_1$ and $P_2$ are two distinct and intersecting planes. Three non-collinear points lie on $P_1$ and another three non-collinear points lie on $P_2$ (none being on line of intersection of planes). Then the maximum number of tetrahedrons formed using these six points, is
  • A
    $20$
  • $15$
  • C
    $10$
  • D
    $5$

Answer

Correct option: B.
$15$
b
Required number of tetrahedrons

$ = \,{}^3{C_3}\, \times \,{}^3{C_1} + {}^3{C_2} \times {}^3{C_2} + {}^3{C_1} \times {}^3{C_3} = 15$

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Similar questions

Let

$M =\left\{( x , y ) \in R \times R : x ^2+ y ^2 \leq r ^2\right\},$

where $r >0$. Consider the geometric progression $a _{ n }=\frac{1}{2^{ n -1}}, n =1,2,3, \ldots$. Let $S _0=0$ and, for $n \geq 1$, let $S _{ n }$ denote the sum of the first $n$ terms of this progression. For $n \geq 1$, let $C_n$ denote the circle with center $\left(S_{n-1}, 0\right)$ and radius $a _{ n }$, and $D _{ n }$ denote the circle with center $\left( S _{ n -1}, S _{ n -1}\right)$ and radius $a _{ n }$.

($1$) Consider M with $r =\frac{1025}{513}$. Let $k$ be the number of all those circles $C _{ n }$ that are inside $M$. Let $l$ be the maximum possible number of circles among these $k$ circles such that no two circles intersect. Then

$(A)$ $k +2 l=22$ $(B)$ $2 k +l=26$ $(C)$ $2 k +3 l=34$ $(D)$ $3 k +2 l=40$

($2$) Consider $M$ with $r =\frac{\left(2^{199}-1\right) \sqrt{2}}{2^{158}}$. The number of all those circles $D _{ a }$ that are inside $M$ is

$(A) 198$ $(B) 199$ $(C) 200$ $(D) 201$

Give the answer or qution ($1$) and ($2$)

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