MCQ
$P_4O_{10}$ reacts with $HNO_3$ to give
- A$N_2O, H_3PO_2$
- B$N_2O_3, H_3PO_4$
- C$NO_2, HPO_3$
- ✓$N_2O_5, HPO_3$
✓
Answer
Correct option: D.
$N_2O_5, HPO_3$
d
The reaction is as follows: $4 HNO _3+ P _4 O _{10} \rightarrow 2 N _2 O _5+4 HPO _3$
The reaction is as follows: $4 HNO _3+ P _4 O _{10} \rightarrow 2 N _2 O _5+4 HPO _3$
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