Question
Pair of numbers, werify that their product = (HCF × LCM)
87, 145
87, 145
✓
Answer
87 and 145
$\begin{array}{c|c}3&87\\\hline29&29\\\hline&1\end{array}$
$\begin{array}{c|c}5&145\\\hline29&29\\\hline&1\end{array}$
We have:
$87=3\times29$
$145=5\times29$
HCF = 29
LCM $=29\times15\times1=435$
Now, HCF × LCM $=29\times435=12615$
Product of the two numbers $=87\times145=12615$
$\therefore$ HCF × LCM = Product of the two numbers.
Verified.
$\begin{array}{c|c}3&87\\\hline29&29\\\hline&1\end{array}$
$\begin{array}{c|c}5&145\\\hline29&29\\\hline&1\end{array}$
We have:
$87=3\times29$
$145=5\times29$
HCF = 29
LCM $=29\times15\times1=435$
Now, HCF × LCM $=29\times435=12615$
Product of the two numbers $=87\times145=12615$
$\therefore$ HCF × LCM = Product of the two numbers.
Verified.
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