MCQ
Particle $A$ is moving along $x$-axis. At time $t=0$, it has velocity of $10\,m / s$ and acceleration $-4\,m / s ^2$. Particle $B$ has velocity of $20\,m / s$ and acceleration $-2\,m / s ^2$. Initially, both the particles are at origin. At time $t=2\,s$, distance between the two particles is $.............\,m$
  • $24$
  • B
    $36$
  • C
    $20$
  • D
    $42$

Answer

Correct option: A.
$24$
a
(a)

At $2 s$

$x_A=10 \times 2-\frac{1}{2} \times 4 \times(2)^2=12\,m$

and $\quad x_B=20 \times 2-\frac{1}{2} \times 2 \times(2)^2$

$=36\,m$

$\therefore$ Distance between $A$ and $B$ at that instant is, $24\,m$.

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