MCQ
$PC{l_5}$ reacts with propanone, to give
- Avic-dichloride
- BPropanal
- Cpropane-chloride
- ✓gem-dichloride
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Reason : $SO_2$ is a reducing agent
$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,}\\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3} - C{H_2} - C = C - CH - C - C{H_2} - C{H_2} - C{H_3}}\\
{|\,\,\,\,\,\,\,\,\,}\\
{{C_2}{H_5}}
\end{array}$

Here $W, Y$ and $Z$ are left, up and right elements with respect to the element $'X'$ and $'X'$ belongs to $16^{th}$ group and $3^{rd}$ period. Then according to given information the incorrect statement regarding given elements is