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यदि $\mathrm{A}$ और $\mathrm{B}$ घटनाएँ इस प्रकार हों कि: $\mathrm{P}(\mathrm{A} \cup \mathrm{B})=\frac{3}{4}$, $P(A \cap B)=\frac{1}{4} \cap P(\bar{A})=\frac{2}{3}$ तो $P(\bar{A} \cap B)$ है :