Download App

STD 11 - 3. Classification of elements and periodicity in properties — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 3. Classification of elements and periodicity in properties4 Marks
Question
Pentavalency in phosphorus is more stable when compared to that of nitrogen even through they belong to same group is due to
✓

Answer

d
Pentavalence in phosphorus is more stable when compared to that of nitrogen even though they belong to same group is due to large size of phosphorus atom and greater ability to accommodate electrons.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

NEET STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

In the ground state of atomic $Fe \,( Z =26)$ the spin-only magnetic moment is ...... $\times 10^{-1} \,BM$. (Round off to the Nearest Integer).

$[$ Given $: \sqrt{3}=1.73, \sqrt{2}=1.41]$

→
Ethyl amine undergoes oxidation in the presence of $KMn{O_4}$ to form
→
Assign $A, B, C, D$ from given type of reaction. $3Mg\left( s \right) + {N_2}\left( g \right) \longrightarrow M{g_3}{N_2}$
→
If the passage of current liberates $H_2$ at cathode and $Cl_2$ at anode then the solution is
→
What will be $IUPAC$ name of compound when allyl and neopentyl joined together 
→
In $\left[ {Cu\,{{\left( {N{H_3}} \right)}_4}} \right]\,S{O_4},\,\,;\,Cu$ has following hybridization
→
The compound($s$) which generate($s$) $\mathrm{N}_2$ gas upon thermal decomposition below $300^{\circ} \mathrm{C}$ is (are)

$(A)$ $\mathrm{NH}_4 \mathrm{NO}_3$   $(B)$ $\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$   $(C)$ $\mathrm{Ba}\left(\mathrm{N}_3\right)_2$  $(D)$ $\mathrm{Mg}_3 \mathrm{~N}_2$

→
For the following reaction scheme (homogeneous), the rate constant has units

$A+B\xrightarrow{K}C$:

→
The $p^H$ of a solution obtained by mixing $10\  ml$ of $0.1\  M$ $HCl$ and $40\  ml$ of $0.2\  M$ $H_2SO_4$ is (Given $log 17=$  $1.23$, $log 5=$  $0.7$, $log 10=$  $1$)
→
The $IUPAC$ name of $\begin{matrix}
   C{{H}_{3}}\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   C{{H}_{3}}-CH-CH-C{{H}_{2}}N{{H}_{2}}  \\
\end{matrix}$ is
→