MCQ
$Ph - CH _{2}- CH = CH - CH _{3}$ $\xrightarrow[{{\text{(ii) }}Alc.\,KOH}]{{{\text{(i) B}}{{\text{r}}_2}}}$
- A$Ph - CH = CH - CH = CH _{2}$
- B$\begin{array}{*{20}{c}}
{Ph - C{H_2} - CH - CH - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,\,\,\,\,OH\,\,\,}
\end{array}$ - ✓$Ph - CH _{2}- C \equiv C - CH _{3}$
- D$Ph - C \equiv C - CH _{2}- CH _{3}$
