MCQ
$Ph - \mathop O\limits^{18} - C{H_3}\xrightarrow{{conc.\,HI}}product$
- ✓$Ph - \mathop O\limits^{18} H$, $CH_3-I$
- B$Ph-I$, $CH_3 \mathop O\limits^{18} H$
- C$Ph-I, CH_3-I$
- D$Ph-OH, CH_3I$
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$\begin{array}{|l|l|l|l|} \hline & Column\,I & & Column\,II \\ & (Reduction\,process) & & (Charge\,required) \\ \hline (a) & 1\,mol\,of\,MnO_4^-\,to\,Mn^{2+} & (p) & 193000\,\,C \\ \hline (b) & 1\,\,mole\,of\,Cr_2O_7^{2-}\,to\,Cr^{3+} & (q) & 289500\,\,C \\ \hline (c) & 1\,\,mole\,of\,Sn^{4+}\,to\,Sn^{2+} & (r) & 482500\,\,C \\ \hline (d) & 1\,mole\,of\,Al^{3+}\,to\,Al & (s) & 579000\,\,C \\ \hline \end{array}$
$I$ . $Zn +$ conc. $HNO_3$ (hot) $\to Zn(NO_3)_2 + X + H_2O$
$II$. $Zn +$ dil. $HNO_3$ (cold) $\to Zn(NO_3)_2 + Y + H_2O$
Compounds $X$ and $Y$ are respectively