MCQ
$pH$ of $ 0.1\, M$ solution of a weak acid $ (HA) $ is $4.50. $ It is neutralised with $NaOH$ solution to decrease the acid content to half $pH$ of the resulting solution
- A$4.50$
- ✓$8$
- C$7$
- D$10$
$pH = pK_a$
$K_a = 0.1 \times {({10^{ - 3.5}})^2} = 0.1 \times {10^{ - 7}} = {10^{ - 8}}$ $⇒$ $pH = 8$
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