MCQ
$pH$ of a solution is $ 5$ . Its hydroxyl ion concentration is
- A$5$
- B$10$
- C${10^{ - 5}}$
- ✓${10^{ - 9}}$
$pOH = 14 - pH = 14 - 5 = 9$
$[O{H^ - }] = {10^{ - pOH}} = {10^{ - 9}}$
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$SO_3(g) \rightleftharpoons SO_2(g)+ \frac{1}{2} O_2(g)$
is $K_c= 4.9 \times 10^{-2}.$ The value of $K_c$ for the reaction
$2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$
will be
