MCQ
$pH$ of a solution of $10\,ml$. $1\,N $ sodium acetate and $50\,ml$ $2\,N$ acetic acid $({K_a} = 1.8 \times {10^{ - 5}}),$ is approximately
- ✓$4$
- B$5$
- C$6$
- D$7$
$pH = - \log \,(1.8 \times {10^{ - 5}}) + \log \frac{{[10]}}{{[100]}}$
$ = - \log \,\,1.8 + 5 + \log \,\,{10^{ - 1}}$
$ = - \;0.2553 + 5 - 1 = 3.7447\,\,\,{\rm{or}}\,\, = 4$
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