MCQ
$pH$ of a solution produced when an aqueous solution of $pH$ $6$ is mixed with an equal volume of an aqueous solution of $pH$ $3 $ is about
- ✓$3.3$
- B$4.3$
- C$4$
- D$4.5$
$pH = 3$ means $[{H^ = }] = {10^{ - 3}}M$
After mixing,
Total $[{H^ + }] = \frac{{({{10}^{ - 6}} + {{10}^{ - 3}})}}{2}$ $ = \frac{{1.001 \times {{10}^{ - 3}}}}{2}$
$ = 5.005 \times {10^{ - 4}}$
$pH = 4 - \log 5.005$ ; $pH = 3.301$.
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