STD 11 - 6.2. Equilibrium - II (icon Equilibrium) — NEET STD 11 Science — Question

$pH =-\log _{10}\left[ H ^{+}\right]$

- $pOH$ is defined as the negative logarithm of Hydroxide ion $( OH -)$ concentration.

$pOH =-\log _{10}\left[ OH ^{-}\right]$

- The concentration of $\left[ H ^{+}\right]$and $\left[ OH ^{-}\right]$is $10^{-7}$ for a neutral solution.

$pH =-\log _{10}\left[10^{-7}\right]$

$pH =7 \log _{10}[10]$

$pH =7$

$pOH =-\log _{10}\left[10^{-7}\right]$

$pOH =7 \log _{10}[10]$

$pOH =7$

- The value of $\log _{10}[10]$ is $1 .$

- Calculate the sum of $pH$ and $pOH$.

$pH + pOH =7+7$

$=14$