MCQ
Phenylmethanol can be prepared by reducing the benzaldehyde with
- A$C{H_3}Br$
- ✓$Zn$ and $HCl$
- C$C{H_3}Br$ and $Na$
- D$C{H_3}I$ and $Mg$
✓
Answer
Correct option: B.
$Zn$ and $HCl$
b
Phenylmethanol can be prepared from benzaldehyde by treating it with zinc in presence of $HCl$. This is categorised as a reduction reaction as hydrogen is added to the molecule during this reaction.Given below is the chemical reaction for the same.
Phenylmethanol can be prepared from benzaldehyde by treating it with zinc in presence of $HCl$. This is categorised as a reduction reaction as hydrogen is added to the molecule during this reaction.Given below is the chemical reaction for the same.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which amino acid does not contain chiral centre
With the help of following reactions, arrange metals $A, B, D$ and $E$ in decreasing order of their reactivity
→$(I)$ $B + AN{O_3} \longrightarrow BN{O_3} + A$
$(II)$ $A + HCl \longrightarrow ACl + \frac{1}{2}\,{H_2}$
$(III)$ $D + ECl \longrightarrow DCl + E$
$(IV)$ $D + HN{O_3} \longrightarrow {H_2}$ gas is not evolved
Which one of the following species responds to an external magnetic field?
Diazonium salt decomposes as ${C_6}{H_5}N_2^ + C{l^ - } \to {C_6}{H_5}Cl + {N_2}$ At ${0\,^o}C$, the evolution of ${N_2}$ becomes two times faster when the initial concentration of the salt is doubled. Therefore, it is
→The half life of a radioactive isotope is $4\, hours$. If the initial mass of isotope is $200\, gram$ then what will be the disintegrated amount of it after $16\, hours$ .......... $gm$
→Decomposition of $H_2O$ follows a first order reaction. In fifty minutes the concentration of $H_2O_2$ decreases from $0.5$ to $0.125\,\min$ one such decomposition. When the concentration of $H_2O_2$ reaches $0.05\, M,$ the rate of formation of $O_2$ will be :
→$CHC{l_3}$ and $ HF$ lead to the formation of a compound of fluorine of molecular weight $70$ . The compound is
→Which of the following are correct statements about ${C_2}{H_5}Br$
→Product $(A)$ of the reaction is
→Correct increasing order of spin magnetic moment (in $B.M.$) for complexes for
→$(I) [FeF_6]^{-3}$
$(II) [V(H_2O)_6]^{+2}$
$(III) [Fe(H_2O)_6]^{+2}$