MCQ
Phosphorous is having three unpaired electrons according to
- ✓Hund’s rule
- BAufbau principle
- CPauli’s exclusion principle
- DHeisenberg’s principle
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$A.\,\,F -CH_2\,\,CH_2\,\,COOH$
$\begin{array}{*{20}{c}}
{B.\,\,Cl - CH - C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$C.\,\,F -CH_2 -COOH$
$D.\,\,Br -CH_2-CH_2 -COOH$
Correct answer is

$| Pt(s)$ At $298\ K$, $E^o_{cell}$ for cell is $- 2.31\ V$ , what will be the $E_{cell}$ at $pH = 1$ ? ........... $\mathrm{Volt}$