MCQ
Phosphorus has the oxidation state of $ +3$ in
- AOrthophosphoric acid
- ✓Phosphorus acid
- CMetaphosphoric acid
- DPyrophosphoric acid
$3 + x - 2 \times 3 = 0$; $x = 6 - 3 = + 3$.
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$(i)$ ${C_4}{H_5}N{H_2}$ $(ii)$ $C{H_3}N{H_2}$
$(iii)$ ${(C{H_3})_2}NH$ $ (iv)$ ${(C{H_3})_3}N$
$k =\left(6.5 \times 10^{12} \,s ^{-1}\right) e ^{-26000 K / T }$
is followed for the decomposition of compound $A$. The activation energy for the reaction is $.....\,kJ$ $mol ^{-1}$. [nearest integer]
(Given: $R =8.314 \,J\, K ^{-1}\, mol ^{-1}$ )
Reason : Red phosphorus consists of $P_4$ tetrahedral units linked to one another to form linear chains.