7. Alcohol, phenol and ethers — Chemistry STD 12 Science — Question

$(I)$ $-OAc$                        $(II)$ $-OMe$

$(III)$ $-O-SO_2-Me$          $(IV)$ $-O-SO_2-CF_3$

The order of leaving power is :

${P} \xrightarrow[\substack{\text { 2. } \mathrm{H}^{+}, \mathrm{H}_2 \mathrm{O} \\ \text { 3. } \mathrm{H}_2 \mathrm{SO}_4, \Delta}]{\text { 1. MeMgBr }}Q \xrightarrow[\text { 2. } \mathrm{Zn}, \mathrm{H}_2 \mathrm{O}]{1 . \mathrm{O}_3} {R} \xrightarrow[\text { 2. } \Delta]{1 . \mathrm{OH}^{-}} {S}$

$1.$ The structure of the carbonyl compound ${P}$ is

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$2.$ The structures of the products ${Q}$ and ${R}$, respectively, are

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$3.$ The structure of the product ${S}$ is

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Give hte answer question $1,2$ and $3.$

Reason : In mercury cell, the electrolyte is a paste of $KOH$ and $ZnO$.