Question
Pipe A can fill an empty tank in 5 hours while pipe B can empty the full tank in 6 hours. If both are opened at the same time in the empty tank, how much time will they take to fill it up completely?

Answer

Pipe A's one hour's work for filling the tank $=\frac{1}{5}$
Pipe B's one hour's work for emptying $=\frac{1}{6}$
Both pipes are opened, then,
Both's one hour's work $=\frac{1}{5}-\frac{1}{6}$
$=\frac{6-5}{30}=\frac{1}{30}$
$\therefore$ The empty tank will be filled in 30 hours.

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