c
(c) Process is isothermal. There fore, \(T =\) constant, \(\left( {P \propto \frac{1}{V}} \right)\) volume is increasing, therefore pressure will decreases.

In chamber \(A\) : \(\Delta P = {P_i} - {P_f} = \frac{{{\mu _A}RT}}{V} - \frac{{{\mu _A}RT}}{{2V}} = \frac{{{\mu _A}RT}}{{2V}}\)…..\((i)\)

In chamber \( B\) : \(1.5\Delta P = {P_i} - {P_f} = \frac{{{\mu _B}RT}}{V} - \frac{{{\mu _B}RT}}{{2V}} = \frac{{{\mu _B}RT}}{{2V}}\)…..\((ii)\)

from equations \((i)\) and \((ii)\) \(\frac{{{\mu _A}}}{{{\mu _B}}} = \frac{1}{{1.5}} = \frac{2}{3}\)

==> \(\frac{{{m_A}/M}}{{{m_B}/M}} = \frac{2}{3}\)

==> \(3{m_A} = 2{m_B}.\)