Question
Planes are drawn parallel to the coordinate planes through the points (3, 0, -1) and (-2, 5, 4).
Find the lengths of the edges of the parallelopiped so formed.

Answer

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Let P ≡ (3, 0, -1), Q ≡ (-2, 5, 4)

PE = Distance between the parallel planes ABCP and FQDE

= |4 + 1| = 5 (These planes are perpendicular to the z-axis)

PA = Distance between the parallel planes ABQF and PCDE

= |-2 - 3| = 5 (These planes are perpendicular to the x-axis)

Similarly, PC = |5 - 0| = 5

Thus, the length of the edges of the parallelepiped are 5, 5 and 5

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