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Oscillations — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysicsOscillations3 Marks
Question
Plot the corresponding reference circle for each of the following simple harmonic motions. Indicate the initial (t = 0) position of the particle, the radius of the circle, and the angular speed of the rotating particle. For simplicity, the sense of rotation may be fixed to be anticlockwise in every case: (x is in cm and t is in s).$\text{x}=3\sin\Big(2\pi\text{t}+\frac{\pi}{4}\Big)$
✓

Answer

$\text{x}=3\sin\Big(2\pi\text{t}+\frac{\pi}{4}\Big)$$=-3\cos\bigg[\Big(2\pi\text{t}+\frac{\pi}{4}\Big)+\frac{\pi}{2}\bigg]=-3\cos\Big(2\pi\text{t}+\frac{3\pi}{4}\Big)$
If this equation is compared with the standard SHM equation $\text{x}=\text{A}\cos\bigg(\Big(\frac{2\pi}{\text{T}}\Big)\text{t}+\phi\bigg),$ then we get:
Amplitude, A = 3cm
Phase angle, $\phi=\frac{3\pi}{4}=135^\circ$
Angular velocity, $\omega=\frac{2\pi}{\text{T}}=2\pi\text{ rad/s}$
The motion of the particle can be plotted as shown in the following figure.

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