MCQ
Polarisation of electrons in acroline may be written as
  • A
    $CH_2^{\delta - } = CH - C{H^{\delta + }} = O$
  • B
    $CH_2^{\delta - } = CH - CH = {O^{\delta + }}$
  • C
    $CH_2^{\delta - } = C{H^{\delta + }} - CH = O$
  • $CH_2^{\delta + } = CH - CH = {O^{\delta - }}$

Answer

Correct option: D.
$CH_2^{\delta + } = CH - CH = {O^{\delta - }}$
d
Polarisation of electrons in acrolein may be written as $\stackrel{+\delta}{CH _2}= CH - CH =\stackrel{-\delta}{ O }$.

$O$ atom is more EN than $C$ atom, so it acquires $(-\delta)$ charge and $C$ atom acquires $(+\delta)$ charge which is transferred to the last $C$ atom.

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