Question
Polarisation of light was first successfully explained by:
✓
Answer
- Electromagnetic wave theory
Electromagnetic wave theory explains light as being composed of electric field vibrating in planes.
Polarisation of light refers to vibrating electric field in a particular plane.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The curve between charge density and distance near $P-N$ junction will be
→Two spheres of radius $a$ and $b$ respectively are charged and joined by a wire. The ratio of electric field of the spheres is
→A conductor has $14.4 \times 10^{-19}$ coulombs positive charge. The conductor has $($Charge on electron $=1.6 \times 10^{-19}$ coulombs$)$
→The molecules having permanent electric dipole moment even in the absence of electric field are called as:
If a piece of metal was thought to be magnet, which one of the following observations would offer conclusive evidence(a) It attracts a known magnet(b) It repels a known magnet(c) Neither (a) nor (b)(d) It attracts a steel screw driver
Pure inductance of $3.0 H$ is connected as shown below. The equivalent inductance of the circuit is
→In the depletion region of a pn junction, there is a shortage of:
In the circuit given, the correct relation to a balanced Wheatstone bridge is
The total mechanical energy of a spring$-$mass system in $1$ simple harmonic motion is $\text{E}=\frac{1}{2}\text{m}\omega^2\text{A}^2.$ Suppose the oscillating particle is replaced by another particle of double the mass while the amplitude A remains the same. The new mechanical energy will:
→A particle moves on the $X-$axis according to the equation $\text{x}=\text{x}_0\sin^2\omega\text{t.}$ The motion is simple harmonic.
→