MCQ
Potential energy of electron present in $He^+$ is
- A$\frac{{{e^2}}}{{2\pi { \in _0}r}}$
- B$\frac{{3{e^2}}}{{4\pi { \in _0}r}}$
- ✓$\frac{{ - {e^2}}}{{2\pi { \in _0}r}}$
- D$\frac{{ - {e^2}}}{{4\pi { \in _0}{r^2}}}$
✓
Answer
Correct option: C.
$\frac{{ - {e^2}}}{{2\pi { \in _0}r}}$
c
$P.E.$ = $ - \frac{{KZ{e^2}}}{r} = \frac{{ - 1}}{{4\pi { \in _0}}} \times \frac{{2{e^2}}}{r} = - \frac{{{e^2}}}{{2\pi { \in _0}r}}$
$P.E.$ = $ - \frac{{KZ{e^2}}}{r} = \frac{{ - 1}}{{4\pi { \in _0}}} \times \frac{{2{e^2}}}{r} = - \frac{{{e^2}}}{{2\pi { \in _0}r}}$
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