Question
Pranav and sarita had set up stalls in a fun fair. Study the data given below and answer the questions.
✓
Answer
Total amount invested by Pranav = 70 + 25 + 45 + 14 + 20 = Rs 174
Amount gained through sale = Rs 160
∴ Selling price is less than invested price.
∴ Pranav incurred a loss in his Pav Bhaji business. Hence, he is disappointed.
Amount gained through sale = Rs 160
∴ Selling price is less than invested price.
∴ Pranav incurred a loss in his Pav Bhaji business. Hence, he is disappointed.
Total amount invested by Sarita = 20 + 10 + 30 + 50 + 20 + 60 = Rs 190
Amount gained by selling = Rs 230
∴ Selling price is more than invested price.
∴ Sarita made profit in her business. Hence, she is happy.
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Kaprekar Number.
i. Take any 4-digit number in which all the digits are not the same.
ii. Obtain a new 4-digit number by arranging the digits in descending order.
iii. Obtain another 4-digit number by arranging the digits of the new number in ascending order.
iv. Subtract the smaller of these two new numbers from the bigger number. The difference obtained will be a 4-digit number. If it is a 3-digit number, put a 0 in the thousands place. Repeat the above steps with the difference obtained as a result of the subtraction.
v. After some repetitions, you will get the number 6174. If you continue to repeat the same steps you will get the number 6174 every time. Let us begin with the number 8531.
8531 → 7173 → 6354 → 3087 → 8352 → 6174 → 6174
This discovery was made by the mathematician, Dattatreya Ramchandra Kaprekar. That is why the number 6174 was named the Kaprekar number.
i. Take any 4-digit number in which all the digits are not the same.
ii. Obtain a new 4-digit number by arranging the digits in descending order.
iii. Obtain another 4-digit number by arranging the digits of the new number in ascending order.
iv. Subtract the smaller of these two new numbers from the bigger number. The difference obtained will be a 4-digit number. If it is a 3-digit number, put a 0 in the thousands place. Repeat the above steps with the difference obtained as a result of the subtraction.
v. After some repetitions, you will get the number 6174. If you continue to repeat the same steps you will get the number 6174 every time. Let us begin with the number 8531.
8531 → 7173 → 6354 → 3087 → 8352 → 6174 → 6174
This discovery was made by the mathematician, Dattatreya Ramchandra Kaprekar. That is why the number 6174 was named the Kaprekar number.
For the pentagon shown in the figure below, answer the following: (Textbook pg. no. 84)
- Write the names of the five vertices of the pentagon.
- Name the sides of the pentagon.
- Name the angles of the pentagon.
- See if you can sometimes find players on a field forming a pentagon.
A pictogram of the types and numbers of vehicles in a city is given below.
Taking 1 picture = 5 vehicles, write the numbers in the pictogram.
Taking 1 picture = 5 vehicles, write the numbers in the pictogram.
The measures of some angles are given below. Write the type of each angle:
- 75°
- 0°
- 215°
- 360°
- 180°
- 120°
- 148°
- 90°
Express each of the following as a Roman numeral:
|
S.No.
|
Numerical
|
|
i
|
164
|
|
ii
|
195
|
|
iii
|
226
|
|
iv
|
341
|
|
v
|
475
|
|
vi
|
596
|
|
vii
|
611
|
|
viii
|
759
|
Arrange the following fractions in descending order:$\frac{5}{7},\frac{9}{14},\frac{17}{21}\ \text{and}\ \frac{31}{42}$
→Arrange the following numbers in descending order:
5032786, 23794206, 5032790, 23756819, 987876
5032786, 23794206, 5032790, 23756819, 987876
Write the names of four of your classmates. Beside each name, write his/her weight in kilograms. Enter this data in a table like the above and make a bar graph.
| Name of classmates | Weight (kg) |
| Rohan | 32 |
| Laxmi | 28 |
| Rakesh | 40 |
| Riya | 36 |
For the above example,
- If Sarita had bought twice as much, would she have gained twice as much?
- What should Pranav do the next time he sets up a stall to sell more pav bhaji and make more gains? (Textbook pg. no. 66)
Simplify:
$7\frac{1}{2}-\Big[2\frac{1}{4}\div\Big\{1\frac{1}{4}-\frac{1}{2}\Big(\frac{3}{2}-\overline{\frac{1}{3}-\frac{1}{6}}\Big)\Big\}\Big]$
→$7\frac{1}{2}-\Big[2\frac{1}{4}\div\Big\{1\frac{1}{4}-\frac{1}{2}\Big(\frac{3}{2}-\overline{\frac{1}{3}-\frac{1}{6}}\Big)\Big\}\Big]$