(image) $+ NaNO_2+HCl \rightarrow $ product
- A

- B

- C

- ✓

(image) $+ NaNO_2+HCl \rightarrow $ product






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$\mathrm{Cu}_{(\mathrm{s})}+2 \mathrm{Ag}^{+}\left(1 \times 10^{-3} \,\mathrm{M}\right) \rightarrow \mathrm{Cu}^{2+}(0.250\, \mathrm{M})+2 \mathrm{Ag}_{(\mathrm{s})}$
$\mathrm{E}_{\mathrm{Cell}}^{\ominus}=2.97\, \mathrm{~V}$
$\mathrm{E}_{\text {cell }}$ for the above reaction is $....\,V.$ (Nearest integer)
[Given : $\log 2.5=0.3979, T=298\, \mathrm{~K}]$

$6 OH ^{-}+ Cl ^{-} \rightarrow ClO _{3}^{-}+3 H _{2} O +6 e ^{-}$
If only $60 \%$ of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce $10\, g$ of $KCIO _{3}$ using a current of $2\, A$ is..........
(Given : $F =96,500\, C\, mol ^{-1}$ molar mass of $\left. KClO _{3}=122\,gmol ^{-1}\right)$