Question
Predict the shape and bond angles in the following molecules:
a. $CF_4$
b.$NF_3$
c. $HCN$
d. $H_2S$
a. $CF_4$
b.$NF_3$
c. $HCN$
d. $H_2S$
✓
Answer
a. $CF _4$ : There are four bond pairs on the central atom. Hence, shape of $CF _4$ is tetrahedral and $F - C - F$ bond angle is $109^{\circ} 28^{\prime}$.
b. $NF _3$ : There are three bond pairs and one lone pair on the central atom. Hence, shape of $NF _3$ is trigonal pyramidal and F-N-F bond angle is less than $109^{\circ} 28^{\prime}$.
c. HCN : There are two bond pairs on the central atom. Hence, shape of HCN is linear and $H - C - N$ bond angle is $180^{\circ}$.
d. $H _2 S$ : There are two bond pairs and two lone pairs on the central atom. Hence, shape of $H _2 S$ is bent or V -shaped and $H - S - H$ bond angle is slightly less than $109^{\circ} 28^{\prime}$.
b. $NF _3$ : There are three bond pairs and one lone pair on the central atom. Hence, shape of $NF _3$ is trigonal pyramidal and F-N-F bond angle is less than $109^{\circ} 28^{\prime}$.
c. HCN : There are two bond pairs on the central atom. Hence, shape of HCN is linear and $H - C - N$ bond angle is $180^{\circ}$.
d. $H _2 S$ : There are two bond pairs and two lone pairs on the central atom. Hence, shape of $H _2 S$ is bent or V -shaped and $H - S - H$ bond angle is slightly less than $109^{\circ} 28^{\prime}$.
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