We get \(k = \frac{{2\pi }}{\lambda } = 0.02\, \Rightarrow \,\lambda = 100\,cm\)
Also, it is given that phase difference between particles \(\Delta \phi = \frac{\pi }{2}.\)
Hence path difference between them
\(\Delta = \frac{\lambda }{{2\pi }} \times \Delta \phi = \frac{\lambda }{{2\pi }} \times \frac{\pi }{2} = \frac{\lambda }{4} = \frac{{100}}{4} = 25\,cm\)
(હવામાં ધ્વનિનો વેગ $330\;m/sec$ છે)