MCQ
Product $(A)$ and $(B)$ in above reaction is
  • A
    $\begin{array}{*{20}{c}}
      {O\,\,\,\,\,\,} \\ 
      {||\,\,\,\,\,\,\,} \\ 
      {{O^ - } - S - O - H,} 
    \end{array}\begin{array}{*{20}{c}}
      {O\,\,\,\,\,\,\,\,\,\,} \\ 
      {||\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {{O^ - } - S - O - C{H_3}} 
    \end{array}$
  • $\begin{array}{*{20}{c}}
      {O\,\,\,\,\,\,\,\,\,\,} \\ 
      {||\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {{O^ - } - S - O - H,} 
    \end{array}$ $\begin{array}{*{20}{c}}
      \,\,\,\,{O\,\,} \\ 
      \,\,\,\,{||\,\,} \\ 
      {{O^ - } - {}_ \oplus S - C{H_3}} \\ 
      \,\,{|\,\,\,} \\ 
     \,\, {{O^ - }\,} 
    \end{array}$
  • C
    $\begin{array}{*{20}{c}}
      {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {{O^ - } - S - O - C{H_3},} 
    \end{array}$ $\begin{array}{*{20}{c}}
      {\,\,\,\,\,\,\,\,O\,\,} \\ 
      {\,\,\,\,\,\,\,\,||\,\,} \\ 
      {{O^\Theta } - {}^ \oplus S - H} \\ 
      {\,\,\,\,\,\,|} \\ 
      {\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
    \end{array}$
  • D
    $\begin{array}{*{20}{c}}
      {\,\,\,\,\,\,\,\,O\,\,} \\ 
      {\,\,\,\,\,\,\,\,||\,\,} \\ 
      {{O^ - } - {}^ \oplus S - O} \\ 
      {\,\,\,\,\,\,|} \\ 
      {\,\,\,\,H} 
    \end{array},\begin{array}{*{20}{c}}
      {\,\,O\,\,} \\ 
      {\,\,||\,\,} \\ 
      {{O^ - } - S - {O^ - }} \\ 
      {||} \\ 
      {\,\,\,\,\,C{H_3}} 
    \end{array}$

Answer

Correct option: B.
$\begin{array}{*{20}{c}}
  {O\,\,\,\,\,\,\,\,\,\,} \\ 
  {||\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {{O^ - } - S - O - H,} 
\end{array}$ $\begin{array}{*{20}{c}}
  \,\,\,\,{O\,\,} \\ 
  \,\,\,\,{||\,\,} \\ 
  {{O^ - } - {}_ \oplus S - C{H_3}} \\ 
  \,\,{|\,\,\,} \\ 
 \,\, {{O^ - }\,} 
\end{array}$
b
(Sulphur is better nucleophile than oxygen.) (But oxygen is better base than  sulphur)

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