

$\xrightarrow{{SOC{l_2}}}B\xrightarrow{{N{H_3}}}C\xrightarrow[{B{r_2}}]{{NaOH}}D$

$CH_3 (CH_2)_8CH_2Br \xrightarrow[benzene]{KCN} CH_3 (CH_2)_8CH_2CN$
Consider the above reaction. The percentage yield of amide product is ...... . (Round off to the Nearest Integer). (Given : Atomic mass : $C : 12.0\, u , H : 1.0 \,u,N : 14.0\, u , O : 16.0\, u , Cl : 35.5\, u )$


$PhC{{O}_{2}}H\xrightarrow[2.\,N{{H}_{3}}]{1.\,PC{{l}_{5}}}A\xrightarrow[2.\,{{H}_{2}}/Ni]{1.\,{{P}_{4}}{{O}_{10}}.heat}B.$ The final product $(B)$ is