MCQ
Product $(A)$ is


- A

- ✓

- C

- D








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STATEMENT-$2$: All chiral molecules have chiral centres.
$R - C \equiv C - R\xrightarrow{{Pd/BaS{O_4}}}A$
$R - C \equiv C - R\xrightarrow{{Na/Liq.\,NH_3}}B$