MCQ
Product $(A)$ is


- A

- ✓

- C

- D








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$Br^-+ CH_3OH \rightarrow BrCH_3 + OH^-,$ is due to
$F_{2(g)} + 2e^- \rightarrow 2F^-_{(aq)}\, ;$ $E^o = + 2.85\, V$
$Cl_{2(g)} + 2e^- \rightarrow 2Cl^-_{(aq)}\, ;$ $E^o = + 1.36\, V$
$Br_{2(l)} + 2e^- \rightarrow 2Br^-_{(aq)}\, ;$ $E^o = + 1.06\, V$
$I_{2(s)} + 2e^- \rightarrow 2I^-_{(aq)}\, ;$ $E^o = + 0.53\, V$
The strongest oxidising and reducing agents respectively are

what is $'B'$ and $'C'$