MCQ
Product $(A)$ of the above reaction is
- A
- ✓
- C
- D
✓
Answer
Correct option: B.
b
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Similar questions
The element expected to form smallest ion to achieve the nearest nobel gas configuration is:
When cold $NaOH$ reacts with $C{l_2}$ which of the following is formed
→Which has $s{p^3}$ hybridization of central atom
→The $IUPAC$ name of $C{H_3}C{H_2}COCl$ is
→Match List - $I$ with List - $II$
→|
List - $I$ (Pair of Compounds) |
List - $II$ (Isomerism) |
|
$A$n-propanol and Isopropanol |
$(I)$ Metamerism |
|
$B$Methoxypropane and ethoxyethane |
$(II)$ Chain Isomerism |
|
$C$Propanone and propanal |
$(III)$ Position Isomerism |
|
$D$Neopentane and Isopentane |
$(IV)$ Functional Isomerism |
Choose the correct answer from the options given below:
Calculate maximum possible heat which can be released if a $4\ l$ aqueous solution is to be formed by mixing appropriate yolumes of $2\ M\ NaOH$ and $3\ M\ H_2SO_4$ solution $\Delta {H_{{\text{neutralisation}}\,\,{\text{SA/SB}}}} = - 14\ kcal/mol$ ......$ kcal$
→$2\, mole$ of $N_2H_4$ loses $16\, mole$ of electron is being converted to a new compound $X$. Assuming that all of the $N$ appears in the new compound. What is the oxidation state of $'N'$ in $X$ ?
→Match List $I$ and List $II$ and pick out correct matching codes from the given choices
→| List $I$ | List $II$ |
| Compound | Structure |
| $(A)$ $ClF_3$ | Square planar |
| $(B)$ $PCl_5$ | Tetrahedral |
| $(C)$ $IF_5$ | Trigonal bipyramidal |
| $(D)$ $CCl_4$ | Square pyramidal |
| $(E)$ $XeF_4$ | $T-$ shaped |
Codes
Product $(Q)$ in this reaction is
→Which of the following elements will have the lowest first ionisation energy