MCQ
Product $(B)$ is


- ✓$\begin{matrix}
Ph-N=C-CN \\
\,\,\,\,\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,\,\,\,\,\,Ph \\
\end{matrix}$ - B$Ph - N = C - Ph$
- C$Ph - N = N - Ph$
- D$Ph -CH = CH - Ph$


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$Ni ( s )+2 Ag ^{+}(0.001 M ) \rightarrow Ni ^{2+}(0.001 M )+2 Ag ( s )$
$($ Given that $E _{\text {cell }}^{\circ}=10.5 \,V , \frac{2.303 RT }{ F }=0.059$ at $298\, K )$
$Z{n^{2 + }} + 2{e^ - } \to Zn$ ; $E = - 7.62\,\,V,$
$F{e^{2 + }} + 2{e^ - } \to Fe$ ; $E = - 7.81\,\,V$
The emf of the cell $F{e^{2 + }} + Zn \to Z{n^{2 + }} + Fe$ is ............ $\mathrm{V}$