MCQ
Product $(B)$ is


- A

- B$CH_3-O-CH_2-CH_2-CH_3$
- ✓$H_2C = CH-CH_2 - O - CH_3$
- D





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[Assume $100 \%$ ionisation of the complex and $CaCl _{2},$ coordination number of $Cr$ as $6,$ and that all $NH _{3}$ molecules are present inside the coordination sphere $]$