MCQ
Product $(C)$ of above reaction is


- A$H_2C = CH_2$
- B$CH_3 - C \equiv C- CH_3$
- ✓$HC \equiv CH$
- D$CH_3 - CH = CH- CH_3$


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$1.\,\,CH_3-C \equiv C -CH_3$
$2.\,\,CH_3 - CH_2 - CH_2 - CH_3$
$3. \,\,CH_3 - CH_2C \equiv CH$
$4.\,\,CH_3 - CH = CH_2$
$CH_3 (CH_2)_8CH_2Br \xrightarrow[benzene]{KCN} CH_3 (CH_2)_8CH_2CN$
$(A)$ $\left. Na _{4}\left[ Fe ( CN )_{5} NOS \right)\right]$
$(B)$ $Na _{4}\left[ FeO _{4}\right]$
$(C)$ $\left[ Fe _{2}( CO )_{9}\right]$