MCQ
Product in above reaction is


- ✓

- B

- C

- D







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$5 \mathrm{Fe}^{2+}+\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+} \rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O}+5 \mathrm{Fe}^{3+}$
${\left( {I} \right)}$ ${{C_6}{H_5}COC{H_3}}$
${\left( {II} \right)}$ ${C{H_3}COC{H_3}}$
${\left( {III} \right)}$ ${C{H_3} - CHO}$
Statement $I$ : Bromination of phenol in solvent with low polarity such as $\mathrm{CHCl}_3$ or $\mathrm{CS}_2$ requires Lewis acid catalyst.
Statement $II$ : The lewis acid catalyst polarises the bromine to generate $\mathrm{Br}^{+}$.
In the light of the above statements, choose the correct answer from the options given below :