
- A

- ✓

- C

- D







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Reason: The electrical conductivity of metals is due to motion of electrons.
| $List-I$ | $List-II$ |
| $A$ $\left( NH _{4}\right)_{2} Cr _{2} O _{7} \stackrel{\Delta}{\longrightarrow}$ | $I$ $H _{2}$ |
| $B$ $KMnO _{4}+ HCl \rightarrow$ | $II$ $N _{2}$ |
| $C$ $Al + NaOH + H _{2} O \rightarrow$ | $III$ ${ O _{2}}$ |
| $D$ $NaNO _{3} \stackrel{\Delta}{\longrightarrow}$ | $IV$ ${ Cl _{2}}$ |
Choose the correct answer from the options given below.
List $-I$
$(A){\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {C_6}{H_6} + CO + HCl\,\xrightarrow{{AlC{l_3}}}\,{C_6}{H_5}CHO$
$(B){\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {C_6}{H_5} + C{H_3}$ $\xrightarrow{{Cr{O_2}C{l_2}}}\,{C_6}{H_5}CHO$
$(C){\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {C_6}{H_5}C{H_2}Br\, + \,C{H_3}Br$ $\xrightarrow{{Na/ether}}\,{C_6}{H_5}C{H_2}C{H_3}$
$(D){\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {C_6}{H_6}\, + \,{(C{H_3})_2}C = C{H_2}$ $\xrightarrow{{{H_2}S{O_4}}}\,{C_6}{H_5}C{(C{H_3})_3}$
List $-II$
$(a)$ Friedel-Crafts reaction
$(b)$ Wurtz-Fitting reaction
$(c)$ Gattermann-Koch Aldehyde synthesis
$(d)$ Etard’s reaction
Compound $'C'$ is