MCQ
Product of the reaction is


- ✓

- B

- C

- D








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${\Lambda ^o}_{NaCl}\, = \,{\lambda ^o}_{N{a^ + }} + {\lambda ^o}_{C{l^{\, - }}}$
Reason : This is according to Kohlrausch law of independent migration of ions
${\left[\mathrm{V}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}, \quad\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}, \quad\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},}$
${\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}}$
[Given atomic numbers: $\mathrm{V}=23, \mathrm{Cr}=24, \mathrm{Fe}=26$,
$\mathrm{Ni}=28, \mathrm{Cu}=29]$